To Find: Stress =? Strain =? elongation =? Given: Initial length of wire = L = 3 m, radius of wire = 0.5 mm = 0.5 × 10 -3 m = 5 × 10 -4 m,Force applied =49 N, Young’s modulus for steel = Y = 2.1 × 10 11 N/m². calculate a) longitudinal stress, b) longitudinal strain c) elongation produced in the body if Y for steel is 2.1 × 10 11 N/m². Now, Young’s modulus of elasticity= Y = Stress / Strain = (1 × 10 7) / ( 5 × 10 -4)Īns.: Stress = 1 × 10 7 N/m², Strain = 5 × 10 -4 , Young’s modulus of elasticity= Y = 2 × 10 10 N/m²Ī mild steel wire of radius 0.5 mm and length 3 m is stretched by a force of 49 N. =? Strain = ?, Young’s modulus of material = Y = ? M, Stretching weight = 102 kg wt = 102 × 9.8 N, Increase in length = l = 0.1 cm Length of wire = L = 2 m, Cross-sectional area = A = 10 -4 Calculate longitudinal stress, longitudinal strain and Young’s modulus of the material of wire. Now, Young’s modulus of elasticity= Y = Stress / StrainĪns.: Stress = 2.5× 10 7 N/m², Strain =1.2 × 10 -4 , Yong’s modulus of elasticity= 2.08 × 10 11 N/m²Ī wire of length 2 m and cross-sectional area 10 -4 m² is stretched by a load 102 kg. To Find: Stress =? Strain =? Young’s modulus of material = Y =? Length of wire = L = 2 m, Diameter of wire = 2 mm, Radius of wire 2/2 = 1 mm =ġ × 10 -3 m, Weight attached = m = 2 kg, Increase in length = l Find the stress, strain and Young’s modulus of the material of the wire.

A wire 2 m long and 2 mm in diameter, when stretched by weight of 8 kg has its length increased by 0.24 mm.

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